1.

Using the data given below find out the strongest reducing agent. `E_(Cr_(2)O_(7)^(2-)//Cr^(3+))^(Theta)=1.33V,E_(Cl_(2)//Cl^(-))^(Theta)=1.36V` `E_(MnO_(4)^(-)//Mn^(2+))^(Theta)=1.51V,E_(Cr^(3+)//Cr)^(Theta)=-0.74V`A. `Cl^(-)`B. `Cr`C. `Cr^(3+)`D. `Mn^(2+)`

Answer» Correct Answer - B
Strongest reducing agent is one which is oxidized most easiliy, i.e., which has highest oxidation potential. Given values are reduction potentials. Reversing the sign will give oxidation potentials.thus, `Cr//Cr^(3+)` will have highest oxidation potential (+0.74V). hence, Cr is oxidized most easiliy `(CrtoCr^(3+)+3e^(-))` and, therefore, is the strongest reducing agent.


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