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Using the information given in example 2, find (i) the greatest height reached by the stone above the ground. (ii) the velocity with which it strikes the ground (iii) time taken to reach the maximum height

Answer» <html><body><p></p>Solution :Let.s be the <a href="https://interviewquestions.tuteehub.com/tag/height-1017806" style="font-weight:bold;" target="_blank" title="Click to know more about HEIGHT">HEIGHT</a> covered in upward motion then <br/> `v^(2)=u^(2)+2gs` <br/> `0=(14.7)^(2)+2xx(-0.8)s` <br/> `rArr s=((14.7)^(2))/(19.6)=11.025m` <br/> `therefore` The greatest height above the ground =s+s <br/> =11.025+196 <br/> =207.025m <br/> (ii) For the <a href="https://interviewquestions.tuteehub.com/tag/downward-2061463" style="font-weight:bold;" target="_blank" title="Click to know more about DOWNWARD">DOWNWARD</a> motion of the stone, <br/> u=0,g=`9.8m//s^(2)`, s=207,028m <br/> <a href="https://interviewquestions.tuteehub.com/tag/using-7379753" style="font-weight:bold;" target="_blank" title="Click to know more about USING">USING</a> `v^(2)=u^(2)+2gs` <br/> `=0+2xx(9.8)xx207.025` <br/> `rArr v=63.7m//s` <br/> (iii) Let t be the <a href="https://interviewquestions.tuteehub.com/tag/time-19467" style="font-weight:bold;" target="_blank" title="Click to know more about TIME">TIME</a> taken to <a href="https://interviewquestions.tuteehub.com/tag/reach-1178062" style="font-weight:bold;" target="_blank" title="Click to know more about REACH">REACH</a> the maximum height. Then, for the upward motion <br/> `u=14.7m//s, v=0g=-9.8m//s^(2)`<br/> Using v=u+gt, we get <br/> `t=(v-u)/(g)=(0-14.7)/(-9.8)=1.5s`</body></html>


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