InterviewSolution
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InterviewSolution
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Using the standard electrode potential, find out the pair between which redox reaction is not feasible. `E^(θ)` values: `Fe^(3+)//Fe^(2+)=0.77, I_(2)//I^(-)=+0.54`, `Cu^(2+)//Cu=+0.34, Ag^(+)//Ag=+0.80V`A. `Fe^(3+)` and `I^(-)`B. `Ag^(+)` and `Cu`C. `Fe^(3+)` and `Cu`D. `Ag` and `Fe^(3+)` |
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Answer» Correct Answer - d (a) `2Fe^(3+)+2e^(-)to2Fe^(2+),E^(@)=+0.77V` `2I^(-)toI_(2)+2e^(-), E^(@)=-0.54V" "`(Sign of `E^(@)` is reversed) `2Fe^(3+)+2I^(-)to2Fe^(2+)+I_(2), E_("cell")^(@) = +0.23V` This reaction is feasible since `E_("cell")^(@)` is positive. (b) `CutoCu^(2+)+2e^(-), E^(@)=-0.34V" "`(Sign of `E^(@)` has been reversed) `2Ag^(+)+2e^(-)to2Ag, E^(@)=+0.80V` `Cu+2Ag^(+)to2Cu^(2+)+2Ag, E^(@)=+0.46V` this reaction is feasible since `E_("cell")^(@)` is positive. (c ) `{:(2Fe^(3+)+2e^(-)to2Fe^(2+),E^(@)=+0.77V),(CutoCu^(2+)+2e^(-),E^(@)=-0.34V):}/(2Fe^(3+)+Cuto2Fe^(2+)+Cu^(2+),E^(@)=+0.43V)" "`(sign of `E^(@)` is reversed) This reaction is feasible since `E_("cell")^(@)` is positive. (d) `Ag toAg^(+)+e^(-),E^(@)=-0.80V" "`(sign of `E^(@)` is reversed) `Fe^(3+)+e^(-)toFe^(2+),E^(@)=+0.77V` `Ag+Fe^(3+)toAg^(+)+Fe^(2+),E^(@)=-0.03V` This reaction is not feasible since `E_("cell")^(@)` is negative |
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