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InterviewSolution
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Using the standard electrode potentials given in the electrode potential series, predict if the reaction between the following is feasible`:` `a. Fe^(3+)(aq)` and `I^(-)(aq)` `b.` `Ag^(o+)(aq)` and `Cu(s)` `c.` `Fe^(3+)(aq)` and `Br^(-)(aq)` `d.` `Ag(s)` and `Fe^(3+)(aq)` `e. ``Br_(2)(aq)` and `Fe^(2+)(aq)`. |
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Answer» The reaction is feasible if the EMF of the cell reaction is positive (i). `Fe^(3+)(aq)+I^(-)(aq)toFe^(2+)(aq)+(1)/(2)I_(2)(g)` i.e., `Pt//I_(2)//I^(-)(aq)||Fe^(3+)(aq)|Fe^(2+)(aq)|Pt` `E_(cell)^(@)=E_(Fe^(3+),Fe^(2+))^(@)-E_(1//2I_(1),I^(-))^(@)` `=0.77-0.54=0.23V` (Feasible) (ii). `2Ag^(+)(aq)+Cu(s)to2Ag(s)+Cu^(2+)(aq)` i.e., `Cu|Cu^(2+)(aq)||Ag^(+)(aq)|Ag` `E_(cell)=E_(Ag^(+),Ag)-E_(Cu^(2+),Cu)^(@)` `=0.80-0.34=0.46V` (feasible) (iii). `Fe^(3+)(aq)+Br^(-)(aq)toFe^(2+)(aq)+(1)/(2)Br_(2)(g)` `E_(cell)^(@)=0.77-1.09=-0.32V` (Not feasible) (iv). `Ag(s)+Fe^(3+)(aq)toAg^(+)(aq)+Fe^(2+)(aq)` `E_(Cell)^(@)=0.77-0.80=-0.03`V (Not feasible) (v). `(1)/(2)Br_(2)(g)+Fe^(+2)(aq)toBr^(-)(aq)+Fe^(3+)(aq)` `E_(cell)^(@)=1.09-0.77=0.32V` (Feasible). |
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