Vector vecA is 2 cm long and is 60^(@)above th e x-axis in the first quadrant, vector vecB is 2cm long and is 60^(0)below the x-axis in the fourth quadrant . Find vecA+vecB.

Vector vecA is 2 cm long and is 60^(@)above th e x-axis in the first q

1.	Vector vecA is 2 cm long and is 60^(@)above th e x-axis in the first quadrant, vector vecB is 2cm long and is 60^(0)below the x-axis in the fourth quadrant . Find vecA+vecB.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`vecR=vecA+vecB`<br/> `R=2 cos <a href="https://interviewquestions.tuteehub.com/tag/60-328817" style="font-weight:bold;" target="_blank" title="Click to know more about 60">60</a>^(0)<a href="https://interviewquestions.tuteehub.com/tag/hati-2693493" style="font-weight:bold;" target="_blank" title="Click to know more about HATI">HATI</a>+2sin60hatj+2 cos 60hati-2sin60hatj`<br/> `vecR = <a href="https://interviewquestions.tuteehub.com/tag/4cos-318914" style="font-weight:bold;" target="_blank" title="Click to know more about 4COS">4COS</a> 60^(0)hati = 2hati`<br/> `:. 2cm `, <a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a> x-axis<br/> <img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_A_C03_SLV_011_S01.png" width="80%"/></body></html>