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Vector vecA is 2 cm long and is 60^(@)above th e x-axis in the first quadrant, vector vecB is 2cm long and is 60^(0)below the x-axis in the fourth quadrant . Find vecA+vecB. |
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Answer» SOLUTION :`vecR=vecA+vecB` `R=2 cos 60^(0)HATI+2sin60hatj+2 cos 60hati-2sin60hatj` `vecR = 4COS 60^(0)hati = 2hati` `:. 2cm `, ALONG x-axis
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