InterviewSolution
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InterviewSolution
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Velocity-time equation of a particle moving in a straight line is, `v=(10+2t+3t^2)` (SI units) Find (a) displacement of particle from the mean position at time `t=1s,` if it is given that displacement is 20m at time `t=0`. (b) acceleration-time equation. |
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Answer» (i) The given euation can be written as, `v=(ds)/(dt)=(10+2t+3t^(2))` or `ds = (10+2t+3t^(2))dt` or `int_(20)^(s)ds= int_(0)^(1)(10+2t+3t^(2))dt` or `s=20 = [10t+t^(2)+t^(3)]_(0)^(1)` or `s=20+12=32 m` (ii) Acceleration - time equation can be obtained by differentiating the given equaiton w.r,t, time, Thus, `a=(dv)/(dt)=(d)/(dt)(10+2t+3t^(2)) or `a=2+6t` |
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