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Water flows through a horizontal tube as shown in figure. If the difference of height of water column in the vertical tubes in 2cm and the areas of corss-section at A and B are 4 cm^(2) respectively. Find the rate of flow of water across any section. .

Answer» <html><body><p><br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/applying-1982651" style="font-weight:bold;" target="_blank" title="Click to know more about APPLYING">APPLYING</a> Bernoulli's <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> at `A` and `B` <br/> `p_(A)+(1)/(2)rho v_(A)^(2)+rhogh_(A)=p_(B)+(1)/(2)rhov_(B)^(2)+rho gh_(B) (h_(A)=h_(B))` <br/> `or, (1)/(2)rho v_(B)^(2)-(1)/(2)rho v_(A)^(2)=rhog (h_(A)=h_(B))` <br/> or `v_(B)^(2)-v_(A)^(2)=2g (h_(A)=h_(B))` <br/> `=2xx10xx0.02` <br/> or `v_(B)^(2) -v_(A)^(2) = 0.4 m^(2)//s^(2)`....(i) <br/> `v_(A)A_(A)=v_(B)A_(B)` <br/> or, `4v_(A)=2v_(B)` <br/> `:. v_(B)=2v_(A)` ...(ii) <br/> <a href="https://interviewquestions.tuteehub.com/tag/solving-1217196" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVING">SOLVING</a> <a href="https://interviewquestions.tuteehub.com/tag/eqs-2072581" style="font-weight:bold;" target="_blank" title="Click to know more about EQS">EQS</a>, (i) and (ii), we get <br/> `v_(A)=0.363 m//s` <br/> <a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> Flow rate`=v_(A)A_(A)` <br/> `=(0.365)(4xx10^(-4))` <br/> `=1.46xx10^(-4) m^(3)//s=146cm^(3)//s`.</body></html>


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