We All Know That A Const Variable Needs To Be Initialized At The Time

1.	We All Know That A Const Variable Needs To Be Initialized At The Time Of Declaration. Then How Come The Program Given Below Runs Properly Even When We Have Not Initialized P? #include<iostream> Void Main( ) { Const Char *p ; P = "a Const Pointer" ; Cout << P ; }
Answer» The OUTPUT of the above PROGRAM is 'A CONST pointer'. This is because in this program p is declared as 'const char' which means that VALUE stored at p will be constant and not p and so the program works properly. The output of the above program is 'A const pointer'. This is because in this program p is declared as 'const char' which means that value stored at p will be constant and not p and so the program works properly.

We All Know That A Const Variable Needs To Be Initialized At The Time Of Declaration. Then How Come The Program Given Below Runs Properly Even When We Have Not Initialized P? #include<iostream> Void Main( ) { Const Char *p ; P = "a Const Pointer" ; Cout << P ; }

Answer»

The OUTPUT of the above PROGRAM is 'A CONST pointer'. This is because in this program p is declared as 'const char*' which means that VALUE stored at p will be constant and not p and so the program works properly.

The output of the above program is 'A const pointer'. This is because in this program p is declared as 'const char*' which means that value stored at p will be constant and not p and so the program works properly.

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We All Know That A Const Variable Needs To Be Initialized At The Time Of Declaration. Then How Come The Program Given Below Runs Properly Even When We Have Not Initialized P? #include&lt;iostream&gt; Void Main( ) { Const Char *p ; P = "a Const Pointer" ; Cout &lt;&lt; P ; }

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We All Know That A Const Variable Needs To Be Initialized At The Time Of Declaration. Then How Come The Program Given Below Runs Properly Even When We Have Not Initialized P? #include<iostream> Void Main( ) { Const Char *p ; P = "a Const Pointer" ; Cout << P ; }