We know that lime required for softening of water is x{temp Ca hardness + 2.Mg hardness + perm(Mg+Fe+3Al)hardness + 1/2 HCL + H2SO4 – NaAlO2 – CO2}-all are in terms of mg of CaCO3. Here x=?(a) 7.4(b) 0.74(c) 74(d) 740I had been asked this question in an online interview.I need to ask this question from Problems, Units and Formulae in portion Water of Applied Chemistry

We know that lime required for softening of water is x{temp Ca hardnes

1.	We know that lime required for softening of water is x{temp Ca hardness + 2.Mg hardness + perm(Mg+Fe+3Al)hardness + 1/2 HCL + H2SO4 – NaAlO2 – CO2}-all are in terms of mg of CaCO3. Here x=?(a) 7.4(b) 0.74(c) 74(d) 740I had been asked this question in an online interview.I need to ask this question from Problems, Units and Formulae in portion Water of Applied Chemistry
Answer» Right choice is (b) 0.74 To elaborate: Lime also reacts with BICARBONATES of Na and K to FORM CARBONATE. Since 100 parts of CaCO3 is equivalent to the 74 parts of Ca(OH)2. so, x=74/100=0.74.

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