What amount of heat will be generated in a coil of resistance `R` due to a charge q passing through it if the current in the coil a. decreases down to zero uniformly during a time interval `t_0`? b. decrases down to zero having its value every `t_0` seconds?A. `(q^(2)ln2)/(3Deltat)R`B. `(q^(2)ln2)/(4Deltat)R`C. `(q^(2)ln2)/(Deltat)R`D. `(q^(2)ln2)/(2Deltat)R`

What amount of heat will be generated in a coil of resistance `R` due

1.	What amount of heat will be generated in a coil of resistance `R` due to a charge q passing through it if the current in the coil a. decreases down to zero uniformly during a time interval `t_0`? b. decrases down to zero having its value every `t_0` seconds?A. `(q^(2)ln2)/(3Deltat)R`B. `(q^(2)ln2)/(4Deltat)R`C. `(q^(2)ln2)/(Deltat)R`D. `(q^(2)ln2)/(2Deltat)R`
Answer» Correct Answer - D Obviously the current through thhe coil is given by `i=i_(0)((1)/(2))^((t)/(Deltat))` Then charge `q=int_(0)^(infty)idt=int_(0)^(infty)i_(0)2^((-t)/(Deltat))dt=(i_(0)Deltat)/(1n2)` So, `i_(0)=(qln2)/(Deltat)` And hence heat generated in the circuit in the time interval `t[0,infty]` `H=int_(0)^(infty)i^(2)Rdt=int_(0)^(infty)[(q1n2)/(Deltat)2^((-t)/(Deltat))]^(2)Rdt=(q^(2)1n2)/(2Deltat)R`

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