1.

What are the conditions under which ΔH = ΔU?

Answer»

1. For any thermodynamic process or a chemical reaction at constant volume, 

ΔV = 0.

2. Since ΔH = ΔU + PΔV, at constant volume ΔH = ΔU.

3. In the reactions, involving only solids and liquids, Δ V is negligibly small, hence ΔH = ΔH.

4. In a chemical reaction, in which number of moles of gaseous reactants and gaseous products are equal, then change in number of moles, 

Δn = n – n = 0. 

Since ΔH = ΔU + ΔnRT, as Δn = 0, ΔH = ΔU.



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