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What are the number of moles of nitrogen in 274 grams of (NH4)2Ce(NO3)6?(a) 16(b) 8(c) 6(d) 4This question was addressed to me during an interview.This intriguing question originated from The Mole topic in portion Moles, Density & Concentration of Basic Chemical Engineering |
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Answer» RIGHT choice is (d) 4 The EXPLANATION is: Molecular Weight of (NH4)2Ce(NO3)6 = 548 grams, => MOLES of (NH4)2Ce(NO3)6 = 274/548 = 0.5, => number of moles of NITROGEN = 0.5*8 = 4. |
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