What do you except the nature of hydrides if formed by the elements of atomic number of 15,9,23,44 with dihydrogen?

What do you except the nature of hydrides if formed by the elements of

1.	What do you except the nature of hydrides if formed by the elements of atomic number of 15,9,23,44 with dihydrogen?
Answer» (i) The element with atomic number (Z)=15 is P and the corresponding hydride is phosphine `[PH_(3)]`. It is covalent in nature. (ii) The elements with atomic number (Z)=19 is K and the corresponding hydride is potassium hybride `(K^(+)H^(-))`. It is ionic in nature. (iii) The element with atomic number (Z)=23 is V(vanadium). It is a transition metal. It forms as interstitial hydride `(VH_(1.6)`. The element with atomic number (Z)= 44 is Rh (Rhuthenium). It is also a transitioin metal but does not not form any hydride due to hydride gap (as it is present in group 8). Out of the hydrides listed, only the ionic hydrides react with water to evolve hydrogen gas. `2K^(+)H^(-)(s)+2H_(2)O(l) to 2KOH(aq)+H_(2)(g)`

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What do you except the nature of hydrides if formed by the elements of atomic number of 15,9,23,44 with dihydrogen?

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