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What happens when a piece of copper is added to (a) an aq solution of FeSO4 (b) an Aq solution of FeCl3? |
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Answer» a. Nothing will happen when the piece of copper is added to FeSO4 because reduction potential E0 Cu2/Cu(0.34) is more than the reduction potential E0(Fe2+/Fe) (0.44 V). b. Copper will dissolve in an aq solution of FeCl3 because reduction potential E0 Fe3+/Fe2+(0.77 V) is more than the reduction potential of E0 Cu2/Cu(0.34) Cu(s) + 2FeCl3 (aq) → Cu2(aq) + 2FeCl2(aq) |
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