1.

What happens when a piece of copper is added to (a) an aq solution of FeSO4 (b) an Aq solution of FeCl3? 

Answer»

a. Nothing will happen when the piece of copper is added to FeSO4 because reduction potential E0 Cu2/Cu(0.34) is more than the reduction potential E0(Fe2+/Fe) (0.44 V). 

b. Copper will dissolve in an aq solution of FeCl3 because reduction potential E0 Fe3+/Fe2+(0.77 V) is more than the reduction potential of E0 Cu2/Cu(0.34) 

Cu(s) + 2FeCl3 (aq) → Cu2(aq) + 2FeCl2(aq) 



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