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What happens when `Cl_(2)` reacts with cold dilute solution of sodium hydroxide? (b) Why does chlorine water lose its yellow colour on standing? |
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Answer» (a) With cold dilute solution of sodium hydroxide , `Cl_(2)` undergoes disproportionation to give a mixture of sodium chloride, `NaCl` and sodium hypochlorite `(NaOCl)`. `Cl_(2)+2NaOH rarr NaOCl+H_(2)O` (b) Cholorine water is yellow due to the presence of hypochlorous acid, `HOCl` on standing, `HOCl` being unstable decomposes to form `HCl`. Hence the yellow colour disappears. `Cl_(2)+H_(2)IO rarr HCl+underset("yellow")(HOCl) rarr underset("colourless")(2HCl)+[O]`. |
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