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What happens when i. Hydrogen is bubbled through an aqueous solution of sulphur dioxide . ii . Aqueous ammonia in added dropwise to a solution of copper sulphate till it is in excess iii Tin in treated with concentrated nitric acid iv `CrCI_(3)` solution is treated with sodium hydroxide and then with hydrogen peroxide v. `Pb_(3)O_(4)` is treated with nitric acid |
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Answer» Sulphate is precipitate `SO_(2) + 2H_(2)S rarr 3S + 2H_(2)O` ii. Ammonia gives deep blue colour with copper sulphide due to the formation of a complex `CaSO_(4) + 2NH_(4)OH rarr Cu(OH)_(2) + (NH_(4))_(2)SO_(4)` `Cu(OH)_(2) + 2NH_(4)OH +(NH_(4))_(2)SO_(4) rarr underset(blue)([Ca(NH_(3))_(4)])SO_(4) + 4H_(2)O` iii. Metastamic acid id formed `Sn + 3HNO_(3) (conc.) rarr H_(2)SnO_(3) + 4NO_(2) + H_(2)O` iv . A yellow solution of sodium chromate is produced `H_(2)O_(2) rarr H_(2)O + O` `2CrCI_(3) + 10NaOH + 3[O] rarr 2NaCrO_(4) + 6 NaCI + 3H_(2)O` Lead dioxide is precipitate `Pb_(3)O_(4) +_ 4HNO_(3) rarr 2Pb(NO_(3))_(2) 2H_(2)O + PbO_(2)` |
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