1.

What happens whenCl2 reacts with hot concentrated solution of NaOH.XeF6 is mixed with SbF5 and heated.

Answer»
  1. Disproportionation reaction takes place in which chlorine from its zero oxidation state in Cl2 gets disproportionate into NaC103 (oxidised form) and NaCl (reduced form). The reaction is
    3Cl2 + 6 NaOH (Hot and cone.) → NaClO3 + 5 NaCl + 3 H2O
  2. XeF6 + SbF5 → [XeF5]+[SbF6]
    XeF6 loses its F ion which is taken by SbF5 to form cationic and anionic species. Due to ionic species, this mixture will conduct electricity in molten state.


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