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What is an equation for a sine curve with amplitude 2 and period 4 pi radians? |
Answer» <strong style="font-size:18px; line-height:25px !important;">Theequation for a sine curve with amplitude 2 and period 4 pi radians isf(x) = 2 sin(x/2).</strong><p>We will be using the phase shift standard form to solve this.</p> | |