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What is `E^(c)._(red)` for the reaction`: Cu^(2+)+2e^(-) rarr Cu` in the half cell `Pt_(S^(2)|CuS|Cu)`. if `E^(c-)._(Cu^(2+)|Cu)` is `0.34V` and `K_(sp)` of `CuS=10^(-35)`?A. `0.34V`B. `-0.6925V`C. `+0.6925V`D. `-0.66V` |
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Answer» Correct Answer - b `E_(S^(2-)|CuS|Cu)=E^(c-)._(Cu^(2+)|Cu)+(0.059)/(2)log K_(sp)CuS` `=0.34+(0.059)/(2)log10^(-35)=-0.925V` |
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