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What is the enthalpy change of 10^oC system if the heat capacity of air at 20^oC is 5 J/^oC and heat capacity of water vapor at 20^oC is 15 J/^oC, enthalpy of vaporization is 10 J, and the humidity is 40%?(a) 58 J(b) 84 J(c) 114 J(d) 135 JThis question was addressed to me by my college professor while I was bunking the class.Enquiry is from Applications of Humidity Chart topic in portion Humidity Charts & their Use, Analysis of the Degrees of Freedom in a Steady – State Process, Solving Material and Energy Balances Using Process and Unsteady State Material and Energy Balances of Basic Chemical Engineering

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Right OPTION is (c) 114 J

The explanation: ∆H = 5(20 – 10) + 0.4*[15(20 – 10) + 10] = 50 + 64 = 114 J.



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