what is the experimental percent of oxygen in a copper oxide if 10g of copper reacted completely with 2.52g of oxygen?

what is the experimental percent of oxygen in a copper oxide if 10g of

1.	what is the experimental percent of oxygen in a copper oxide if 10g of copper reacted completely with 2.52g of oxygen?
Answer» EXPLANATION:RECALL that by using the molar mass of an element and the mass of the element in the sample, you can find the amount of moles in the sample. We're gonna find the moles of copper and oxygen within the sample of copper oxide.Calculate the moles of copper givenRemember that moles =massmolarmass The molar mass of copper is 63.55gmol−1 , as the ATOMIC mass of an element corresponds to its molar mass in grams.n(Cu)=1.50g63.55gmol−1=0.0236...molCu Calculate the moles of oxygen in the final sample of copper oxide.Mass of oxygen = mass of copper oxide - initial mass of copperm(O)=2.14g−1.50g=0.64g Molar mass of oxygen = 16.00gmol−1 Now that we have the mass and the molar mass, we can work out the moles.n(O)=0.64g16.00gmol−1=0.04molO Now that we have the moles of copper and oxygen in the sample, compare the mole RATIO. Cu:O=0.0236:0.04≈3:5 Therefore, the empirical formula is Cu3O5 based on the data from the experiment.