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| 1. |
What is the phase difference the velocity and acceleration of a particle executing SHM? |
| Answer» <html><body><p>`pi`<br/>`0.707pi`<br/><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a><br/>`0.5pi`</p>Solution :Displacement of <a href="https://interviewquestions.tuteehub.com/tag/sho-630770" style="font-weight:bold;" target="_blank" title="Click to know more about SHO">SHO</a> `y= A sin omega t` <br/> <a href="https://interviewquestions.tuteehub.com/tag/instantaneous-516608" style="font-weight:bold;" target="_blank" title="Click to know more about INSTANTANEOUS">INSTANTANEOUS</a> velocity `v= (<a href="https://interviewquestions.tuteehub.com/tag/dy-433642" style="font-weight:bold;" target="_blank" title="Click to know more about DY">DY</a>)/(dt)= A omega cos omega t` <br/> `=A omega sin(omega t +(pi)/(2))` <br/> and instantaneous acceleration <br/> `a= (<a href="https://interviewquestions.tuteehub.com/tag/dv-433533" style="font-weight:bold;" target="_blank" title="Click to know more about DV">DV</a>)/(dt)= -omega^(2)y = -omega^(2) [A sin omega t]` <br/> `therefore a= A omega^(2) sin (omega t+pi)`. <br/> Hence, phase difference between instantaneous velocity and acceleration. <br/> `=|(pi)/(2)-pi|=|-(pi)/(2)|=0.5pi`.</body></html> | |