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What is the time period of ratation of the earth around its axis so that the objects at the equator becomes weightless ? (g = 9.8 m//s^(2), Radius of earth= 6400 km) |
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Answer» Solution :G at the equator is `g_(0) = g-g_(0) = g - R omega^(2)` If bodies are to BECOME WEIGHTLESS at the equator, `g_(0) = 0`. `0 = g - R omega^(2) rArr R omega^(2) = g""omega = sqrt((g)/(R))` Time period of rotation, `T = (2pi)/(omega) = 2pi sqrt((R)/(g))` `R = 6400 xx 10^(3)m, g = 9.8 m//s^(2)` `T = 2pi sqrt((6.4 xx 10^(6))/(9.8)) = 5078 s = 84` minute 38s. |
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