1.

What is the time period of ratation of the earth around its axis so that the objects at the equator becomes weightless ? (g = 9.8 m//s^(2), Radius of earth= 6400 km)

Answer»

Solution :G at the equator is
`g_(0) = g-g_(0) = g - R omega^(2)`
If bodies are to BECOME WEIGHTLESS at the equator, `g_(0) = 0`.
`0 = g - R omega^(2) rArr R omega^(2) = g""omega = sqrt((g)/(R))`
Time period of rotation, `T = (2pi)/(omega) = 2pi sqrt((R)/(g))`
`R = 6400 xx 10^(3)m, g = 9.8 m//s^(2)`
`T = 2pi sqrt((6.4 xx 10^(6))/(9.8)) = 5078 s = 84` minute 38s.


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