What is the work done in taking an object of mass 1kg from the surface of the earth to a height equal to the radius of the earth ? (G = 6.67 xx 10^(-11) Nm^(2)//Kg^(2), Radius of the earth = 6400 km, Mass of the earth = 6 xx 10^(24) kg.)

What is the work done in taking an object of mass 1kg from the surface

1.	What is the work done in taking an object of mass 1kg from the surface of the earth to a height equal to the radius of the earth ? (G = 6.67 xx 10^(-11) Nm^(2)//Kg^(2), Radius of the earth = 6400 km, Mass of the earth = 6 xx 10^(24) kg.)
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The work <a href="https://interviewquestions.tuteehub.com/tag/done-2591742" style="font-weight:bold;" target="_blank" title="Click to know more about DONE">DONE</a> in taking an <a href="https://interviewquestions.tuteehub.com/tag/object-11416" style="font-weight:bold;" target="_blank" title="Click to know more about OBJECT">OBJECT</a> to a height <br/> `= (GMm)/(R(R+h)) , ""` Here hR <br/> `= (6.67 xx <a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>^(-11) xx 6 xx 10^(24) xx 1)/(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> xx 6.4 xx 10^(6)) = 3.127 xx 10^(7)J`.</body></html>