What mass of MnO2 (in grams ) is required to produce 1.12 litres of ch – InterviewSolution

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1.	What mass of MnO2 (in grams ) is required to produce 1.12 litres of chlorine gas at STP acccording to the given equation? (upto two decimals) MnO2 (s)+ 4HCl (aq)→MnCl2 (aq)+ 2H2O (l)+ Cl2 (g) Atomic masses of H = 1 u, Cl = 35.5 u, Mn = 55 u, O = 16 u4.35
Answer» What mass of ${MnO}_{2}$ (in grams ) is required to produce 1.12 litres of chlorine gas at STP acccording to the given equation? (upto two decimals) ${MnO}_{2} (s) + 4HCl (aq) \to {MnCl}_{2} (aq) + {2H}_{2} O (l) + {Cl}_{2} (g)$ Atomic masses of H = 1 u, Cl = 35.5 u, Mn = 55 u, O = 16 u 4.35

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