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What mass of Na2CO3 is required to prepare 0.5 molar solution?

Answer» WEIGHT of NA 2 CO 3 = 1000Molarity×Mo1.wt.×V (where V is in ML).SUBSTITUTING values in the above EQUATION, we get-Weight of Na 2 CO 3 = 10000.1×106×500 =5.3 g.


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