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What mass of sodium hydroxide must be dissovled in 500 mL of solution so that the strength of the solution may be 10 g/L ?

Answer» Strength of solution = `("Mass of solute")/("Volume of solution in litres")`
Strength of solution = 10 g/L = `10 gL^(-1)`
Volume of solution = 500 mL = 0.5 L
`therefore` Mass of NaOH (solute) = `(10 gL^(-1)) xx (0.5 L) = 5 g`


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