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What mass of zinc can be produced by the electrolysis of zinc sulphate solution when a steady current of 0.015 ampere is passed for 15 minutes ? Given that atomic mass of zinc is 65.4 amu ? |
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Answer» Quantity of charge passed (Q) `= "Current in amperes" xx"Time in seconds"` `=(0.015 A)xx(15xx60)s=13.5 A s=13.5 C` Gram equivalent mass of zinc`=(65.4)/(2)=32.7` Now, `" " 96500" C"` of charge deposit zinc =32.7 g 13.5 C charge will deposit zinc `=((32.7 g))/((96500 C))xx(13.5 C)=4.57xx10^(-3) g` |
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