1.

What will be the electron’s potential energy in eV in first orbit of hydrogen atom?

Answer»

Potential energy Un = \(-\frac{K Z e^{2}}{r_{n}}\)
Total energy En = \(-\frac{1}{2} \frac{K Z e^{2}}{r_{n}}\)
En = \(\frac{1}{2}\) (Un)
Un = 2En
Total energy in first orbit En = -13.6 eV
Un = 2(-13.6)eV
Un = -27.2 eV



Discussion

No Comment Found