1.

What will be the emf of given cell - `Pt |H_(2) (P_(1)) | H_((aq))^(+) | | H_(2)(P_(2)) |Pt` ?A. `(RT)/(2F) "log"_(e) (P_(1))/(P_(2))`B. `(RT)/(F) "log"_(e) (P_(1))/(P_(2))`C. `(RT)/(F) "log"_(e) (P_(2))/(P_(1))`D. `(RT)/(2F) "log"_(e)(P_(2))/(P_(1))`

Answer» Correct Answer - A
At anode , `H_(2)(P_(1)) to 2 H^(+) + 2e^(-)`
At cathode ` 2 H^(+) + 2e to H_(2)(P_(2))`
`E_("cathode") = (-RT)/(2F) "ln" (P_(2))/([H^(+)]^(2))` and
`E_("anode") = (-RT)/(2F) "ln" ([H^(+)]^(2))/(P_(1))`


Discussion

No Comment Found

Related InterviewSolutions