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What will be the grouping of cells when the current in the circuit is \(\frac {ne}{(R + nr)}\)?(a) Parallel grouping(b) Series grouping(c) Mixed grouping(d) When there is no groupingI had been asked this question by my school teacher while I was bunking the class.The query is from Current Electricity topic in chapter Current Electricity of Physics – Class 12

Answer»

The correct CHOICE is (B) Series grouping

For explanation: When n identical cells, each of emf ‘E’ and internal resistance ‘r’ are connected to the external resistance ‘R’ in series, its called series grouping. In series grouping eeq = ne and REQ = nr Therefore, current in the circuit (I) = \(\frac {ne}{(R + nr)}\).



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