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What will be the molar conductivity of Al 3+ ions at infinite dilution if molar conductivity of `Al^(2) (SO_(4))_(3)`is 858 S `cm^(2)` `"mol" ^(-1)` and ionic conductance of `SO_(4)^(2-)` is 160 S `cm^(2) "mol" ^(-1)` at infinite dilution ?A. 189 S `"cm"^2 "mol"^(-1)`B. 698 S `"cm"^2 "mol"^(-1)`C. 1018 S `"cm"^2 "mol"^(-1)`D. 429 S `"cm"^2 "mol"^(-1)` |
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Answer» Correct Answer - A `Lambda_(Al_2(SO_4)_3)^@=2Lambda_(Al^(3+))^@+3Lambda_(SO_4^(2-))^@` `Lambda_(Al^(3+))^@=(Lambda_(Al_2(SO_4)_3)^@-3Lambda_(SO_4^(2-))^@)/2` `=(858-(3xx160))/2=189 S cm^2 mol^(-1)` |
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