What will happen to the value of emf of the following cell if the cencentration of the electrolyte in the anode compartment is increased ? `Zn | Zn^(2+)(0.1 M)||Cu^(2+)(0.1 M) Cu`.

What will happen to the value of emf of the following cell if the cenc

1.	What will happen to the value of emf of the following cell if the cencentration of the electrolyte in the anode compartment is increased ? `Zn \| Zn^(2+)(0.1 M)\|\|Cu^(2+)(0.1 M) Cu`.
Answer» According to Nernst equation `E_(cell)=E_(cell)^(@)-(0.0591)/(2)"log"([Zn^(2+)])/([Cu^(2+)]` If the concentration of the `Zn^(2+)` is increased, emf of the cell will decrease.

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What will happen to the value of emf of the following cell if the cencentration of the electrolyte in the anode compartment is increased ? `Zn | Zn^(2+)(0.1 M)||Cu^(2+)(0.1 M) Cu`.

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