1.

When 1 g of water 100^(@) C is converted into steam at100^(@)C,. It occupies a volumn of 1671 cc at normal atmospheric pressure . Find the increase in internal energy of the molecules of steam.

Answer»

Solution :`1" atmosphere" = 1.013xx10^(5) Nm^(-2)` ,
volume of 1 gm of water, `V_(1) = 1cc = 10^(-6)m^(3)`,
volume of steams = `1671 cc =1671xx10^(-6) m^(3)`
External WORK done dW = `P(V_(2)-V_(1)) = 1.013xx10^(5)(1671xx10^(-6) -1xx10^(-6))=1.013xx167=169.2 J`.
Specific latent heat of vaporisation of steam=540cal/g. So, heat supplied to CONVERT 1g of water into steam.
`Delta Q = 540xx4.2J=2268J`
By first LAW of THERMODYNAMICS
`Delta U = Delta Q-Delta W = 2268-169.2=2098.8J`


Discussion

No Comment Found