InterviewSolution
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InterviewSolution
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When `2 g` of a gas `A` is introduced into an evacuated flask kept at `25^(@)C`, the pressure is found to be `1 atm`. If `3 g` of another gas `B` is then heated in the same flask, the total pressure becomes `1.5 atm`. Assuming ideal gas behaviour, calculate the ratio of the molecular weights `M_(A)` and `M_(B)`.A. `1:1`B. `1:2`C. `2:3`D. `1:4` |
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Answer» Correct Answer - C After the introduction of `3 g` of `B` the pressure became half its number of mole of `B` `PV=nRT` `n=(w)/(M)implies (w_(A))/(M_(A))=(w_(B))/(M_(B))` or `(2)/(M_(A))=(3)/(M_(B)) or (M_(A))/(M_(B))=(2)/(3)` |
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