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When a colourless gas is passed through bromine water only decolourisation takes place The gas isA. `SO_2`B. HBrC. HCID. `H_2S` |
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Answer» Correct Answer - A `Br_2` cannot oxidise HBr or HCl. `Br_2` oxidises `H_2S` to S. `H_2S+Brto2HBr + S` In the reaction, brown colour of the `Br_2` water is decolourised but milkiness due to colloidal sulphur appears. `Br_2` oxidise `SO_2` to `H_2SO_4` `({:(" "Br_2+H_2O,to2HBr+O),(H_2O+SO_2+O,toH_2SO_4):})/ul(Br_2+2H_2O+SO_2to2HBr+H_2SO_4)` In this reaction only decolorization of `Br_2` takes place. |
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