When a particle is performing linear SHM its K.E. is two times its P.E. at a position A and its P.E. is two times its K.E. at another position B. Find the ratio of K.E, at A to K.E. at B.

When a particle is performing linear SHM its K.E. is two times its P.E

1.	When a particle is performing linear SHM its K.E. is two times its P.E. at a position A and its P.E. is two times its K.E. at another position B. Find the ratio of K.E, at A to K.E. at B.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :TE at A = K.E. at A+P.E at A.<br/> But K.E. at A= <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>(P.E. at A) <br/> `P.E. "at" A= (<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)/(2)(K.E. at A)= (3)/(2)K.E. at A` <br/> Similarly, T.E at <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a> = K.E. at B + P.E. at B.<br/> But P.E, at B = 2(K.E. at B) <br/> T.E. at B = K.E. at B+ 2 (K.E. at B) = 3 K.E. at B. <br/> By the principle of <a href="https://interviewquestions.tuteehub.com/tag/conservation-929810" style="font-weight:bold;" target="_blank" title="Click to know more about CONSERVATION">CONSERVATION</a> of energy <br/> T.E. at A=T.E. at `B= (3)/(2)K.E`. <br/> at `A= 3K.E at B= ("K.E. at A")/("K.E. at B")`</body></html>