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When a system is taken from stata a to state b along the path acb as shown in figure, 60 J of heat flows into the system and 30 J of work is done by the system. Along the path adb, if the work done by the system is 10 J, heat flow into the system is |
Answer» <html><body><p>100 J<br/>20 J<br/>80 J<br/>40 J</p>Solution :According to first law of thermofdynamics,<br/> For the path <a href="https://interviewquestions.tuteehub.com/tag/acb-361404" style="font-weight:bold;" target="_blank" title="Click to know more about ACB">ACB</a>, `Q_(acb) = Delta U_(acb) + W_(acb)` <br/> `:. Delta U_(acb) = Q_(acb) - W_(acb) = 60 J - 30 J = 30 J` <br/> For the path adb, `Q_(adb) = Delta U_(adb) + W_(adb)` <br/> As change in internal energy is path <a href="https://interviewquestions.tuteehub.com/tag/independent-505826" style="font-weight:bold;" target="_blank" title="Click to know more about INDEPENDENT">INDEPENDENT</a>, so `Delta U_(acb) = Delta U_(adb)` <br/> `:. Q_(adb) = 30 J + 10 = 40 J`</body></html> | |