When `CuSO_(4)` is electrolysed, using Pt electrodesA. Copper is liberated at cathode and sulphur at anodeB. Copper is liberated at cathode and oxygen at anodeC. Sulphur is liberated at cathode and oxygen at anodeD. Oxygen is liberated at cathode and copper at anode

When `CuSO_(4)` is electrolysed, using Pt electrodesA. Copper is liber

1.	When `CuSO_(4)` is electrolysed, using Pt electrodesA. Copper is liberated at cathode and sulphur at anodeB. Copper is liberated at cathode and oxygen at anodeC. Sulphur is liberated at cathode and oxygen at anodeD. Oxygen is liberated at cathode and copper at anode
Answer» Correct Answer - B (b) `CuSO_(4)overset((aq)) to Cu^(2+)(aq)+SO_(4)^(2-)(aq)` `H_(2)O overset((aq))hArr H^(+)(aq)+OH^(-)(aq)` At cathode : `Cu^(2+)(aq)+2e^(-) to Cu(s)` At anode : `4OH^(-)(aq) to 2H_(2)O(aq)+O_(2)(g)+4e^(-)`

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Define molar conductivity of a solution and explain how molar conductivity changes with change in concentration of a solution for a weak and a strong electrolyte.
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Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^(-)`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
Based on the data given below, the correcy order of reducing power is: `Fe_((aq.))^(3+) + e rarr Fe_((aq.))^(2+), E^(@) = +0.77 V` `Al_((aq.))^(3+) + 3e rarr Al_((s)), E^(@) = -1.66 V` `Br_(2(aq.)) + 2e rarr 2Br_((aq.))^(-), E^(@) = +1.08 V`A. `Br^(-) lt Fe^(2+) lt Al`B. `Fe^(2+) lt Al lt Br^-`C. `Al lt Br^(-) lt Fe^(2+)`D. `Al lt Fe^(2+) lt Br^(-)`
What are elementary reactions ?

When `CuSO_(4)` is electrolysed, using Pt electrodesA. Copper is liberated at cathode and sulphur at anodeB. Copper is liberated at cathode and oxygen at anodeC. Sulphur is liberated at cathode and oxygen at anodeD. Oxygen is liberated at cathode and copper at anode

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