When electromagnetic radiaiton of wavelength `300 nm` falls on the surface of sodium electrons are emitted with a kinetic enegry of `1.68xx10^(5)Jmol^(-)`. What is the minimum enegry needed to remove an electorn from sodium? Strategy: The minimum enegry required to remove an electron from target metal is called work function `W_(0)` of the metal. It can be calculated from Eq., provided we know the energy of the incident photon and kinetic enegry of a single photoelectorn.

When electromagnetic radiaiton of wavelength `300 nm` falls on the sur

1.	When electromagnetic radiaiton of wavelength `300 nm` falls on the surface of sodium electrons are emitted with a kinetic enegry of `1.68xx10^(5)Jmol^(-)`. What is the minimum enegry needed to remove an electorn from sodium? Strategy: The minimum enegry required to remove an electron from target metal is called work function `W_(0)` of the metal. It can be calculated from Eq., provided we know the energy of the incident photon and kinetic enegry of a single photoelectorn.
Answer» Step `1:` Calculating the enegry `(E)` of incident photon: `E = hv = (hc)/(lambda)` `=((6.6xx10^(-34)Js)(3.0xx10^(8)ms^(-1)))/((300xx10^(-9)m))` `= 6.6 xx 10^(-19)J` Step `2:` Calculating the kinetic enegry of a single photoelecton: `KE = ((1.68xx10^(5)Jmol^(-1)))/(6.022xx10^(23)e mol^(-1))` `0.279 xx 10^(18)Je^(-1)` `= 2.79 xx 10^(-19) Je^(-1)` Step `3:` Calculating the minimun energy needed to remove an electorn: `hv = hv_(0) +kE` `:. hv_(0) = hv - kE` `=(6.6 xx 10^(19)J)-(2.79 xx 10^(-19)J)` `= 3.81 xx 10^(-19) J`

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