When equal volumes of two metals are mixed together, the specific gravity of alloy is 4. When equal masses of the same two metals are mixed together, the specific gravity of the alloy now becomes 3. Find specific gravity of the alloy now becomes 3. Find specific gravity of each metal.

When equal volumes of two metals are mixed together, the specific grav

1.	When equal volumes of two metals are mixed together, the specific gravity of alloy is 4. When equal masses of the same two metals are mixed together, the specific gravity of the alloy now becomes 3. Find specific gravity of the alloy now becomes 3. Find specific gravity of each metal.
Answer» SOLUTION :In CASE of mixture, `rho_("mix")=(m_(1)+m_(2))/(v_(1)+v_(2))`. When equal volumes are mixed, `4=(vrho_(1)+vrho_(2))/(V+v)=(rho_(1)+rho_(2))/(2)......(1)` When equal masses are mixed, `3=(m+m)/((m)/(rho_(1))+(m)/(rho_(2)))=(2rho_(1)rho_(2))/(rho_(1)+rho_(2))....(II)` Therefore, from (i) and (ii) specific gravity of the metals are 2 and 6.