When equal volumes of two metals are mixed together, the specific gravity of alloy is 4. When equal masses of the same two metals are mixed together, the specific gravity of the alloy now becomes 3. Find specific gravity of the alloy now becomes 3. Find specific gravity of each metal.

When equal volumes of two metals are mixed together, the specific grav

1.	When equal volumes of two metals are mixed together, the specific gravity of alloy is 4. When equal masses of the same two metals are mixed together, the specific gravity of the alloy now becomes 3. Find specific gravity of the alloy now becomes 3. Find specific gravity of each metal.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :In <a href="https://interviewquestions.tuteehub.com/tag/case-910082" style="font-weight:bold;" target="_blank" title="Click to know more about CASE">CASE</a> of mixture, `rho_("mix")=(m_(1)+m_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(v_(1)+v_(2))`. <br/> When equal volumes are mixed, <br/> `4=(vrho_(1)+vrho_(2))/(<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>+v)=(rho_(1)+rho_(2))/(2)......(1)` <br/> When equal masses are mixed, <br/> `3=(m+m)/((m)/(rho_(1))+(m)/(rho_(2)))=(2rho_(1)rho_(2))/(rho_(1)+rho_(2))....(<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>)` <br/> Therefore, from (i) and (ii) specific gravity of the metals are 2 and 6.</body></html>