When excess lead nitrate solution was added to a solution of sodium su

1.	When excess lead nitrate solution was added to a solution of sodium sulphate, 15.15 g of lead sulphate were precipitated. What mass of sodium sulphate was present in the original solution? Na2SO4 + Pb(NO3)2 → PbSO4 + 2NaNO3 [Na = 23, S = 32, O = 16, Pb = 207, N = 14]
Answer» When excess lead nitrate solution was added to a solution of sodium sulphate, 15.15 g of lead sulphate were precipitated. What mass of sodium sulphate was present in the original solution? Na₂SO₄ + Pb(NO₃)₂ → PbSO₄ + 2NaNO₃ [Na = 23, S = 32, O = 16, Pb = 207, N = 14]

When excess lead nitrate solution was added to a solution of sodium sulphate, 15.15 g of lead sulphate were precipitated. What mass of sodium sulphate was present in the original solution? Na2SO4 + Pb(NO3)2 → PbSO4 + 2NaNO3 [Na = 23, S = 32, O = 16, Pb = 207, N = 14]

Answer»

When excess lead nitrate solution was added to a solution of sodium sulphate, 15.15 g of lead sulphate were precipitated.

What mass of sodium sulphate was present in the original solution?

Na₂SO₄ + Pb(NO₃)₂ → PbSO₄ + 2NaNO₃

[Na = 23, S = 32, O = 16, Pb = 207, N = 14]