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When forces `F_(1)` , `F_(2)` , `F_(3)` are acting on a particle of mass m such that `F_(2)` and `F_(3)` are mutually prependicular, then the particle remains stationary. If the force `F_(1)` is now rejmoved then the acceleration of the particle isA. `F_(1)//m`B. `F_(2)F_(3)//mF_(1)`C. `(F_(2)-F_(3))//m`D. `F_(2)//m` |
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Answer» Correct Answer - A For equilibrium of system, `F_(1)=sqrt(F_(2)^(2)+F_(3)^(2)` . As `theta=90^(@)` . In the absence of force `F_(1)` , Acceleration`=("Net force")/("Mass")` . `=sqrt(F_(2)^(2)+F_(3)^(2))/m=F_(1)/(m)` . |
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