When `[Ni(NH_(3))_(4)]^(2+)` is treated with conc `HCI`, two compounds having the formula `Ni(NH_(3))(2)CI_(2)` are formed. A solution of I reacts with oxalic acid to form `Ni(NH_(3))_(2)(C_(2)O_(4))`. II does not react with oxalic acid. Deduce the configuration of I and II and the geometry of Ni (II) complexes .A. (a) (I) cis, (II) trans, both tetrahedralB. (b) (I) cis, (II) trans, both square planarC. (c) (I) trans, (II) cis, both tetrahedralD. (d) (I) trans, (II) cris, both square planar

When `[Ni(NH_(3))_(4)]^(2+)` is treated with conc `HCI`, two compounds

1.	When `[Ni(NH_(3))_(4)]^(2+)` is treated with conc `HCI`, two compounds having the formula `Ni(NH_(3))(2)CI_(2)` are formed. A solution of I reacts with oxalic acid to form `Ni(NH_(3))_(2)(C_(2)O_(4))`. II does not react with oxalic acid. Deduce the configuration of I and II and the geometry of Ni (II) complexes .A. (a) (I) cis, (II) trans, both tetrahedralB. (b) (I) cis, (II) trans, both square planarC. (c) (I) trans, (II) cis, both tetrahedralD. (d) (I) trans, (II) cris, both square planar
Answer» Correct Answer - B Chelate ligands i.e. oxalato being too small to span the trans-positions and thus prefer to occupy the cis-position. So (I) is cis and (II) is trans. Platinum is in `+2` oxidation state with `5d^8` valence shell electron configuration. This configuration has higher CFSE and thus favours square planar geometry.

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