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When same quantity of electricity is passed for half an hour, the amount of Cu and Cr deposited are respectivley 0.375g and 0.30g. Radio of electrochemical equivalents of Cu and Cr isA. 0.8B. 1.25C. 2.5D. 1.62. |
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Answer» Correct Answer - B Weights deposited are in the ratio of their eq. wts. `((W_(2))/(W_(2))=(E_(1))/(E_(2)))` Now Z= E/96500 i.e. Z`prop` E `therefore (W_(1))/(W_(2))=(Z_(1))/(Z_(2))=(0.375)/(0.300)=1.25` |
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