InterviewSolution
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InterviewSolution
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When we analyse the projectile motion from any accelerated frame `O` as `vecr_(o),vecu_(o)` and `veca_(o)` respectively, express the following terms, `vecr_(pO)+veca_(p)-vecr_(O),vecu_(pO)=vecu_(p)-vecu_(O)` and `veca_(pO)=veca_(p)-veca_(O)` where `P` stands for projectile. Then using the following kinematical equations of the projectile (For constant acceleration) relative to the accelerating frame ,we have `vecS_(pO)=vecu_(pO)t+1/2veca_(pO)t^(2),vecv_(pO)` `=vecu_(pO)+veca_(pO)t` and `v_(pO)^(2)=u_(pO)^(2)+2veca.vecs_pO` Using the above expressions, anwer the following question:A projectile has initial velocity `v_(0)` realtive to the large plate which is moving with a constant upward acceleration a. Which of the following remains equal for the observers `A` and `B`? A. Maximum heightB. RangeC. Time of flightD. Angle of projection |
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Answer» Correct Answer - D Angle of projection remains equal for both `A&B`. |
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