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-where 0 < x < 1 and 0<p<π/2,ir" Let y= sinThen d is equal to:dxdx |
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Answer» For this you should know the formula of inverse trigonometric functions . So sin^-1(2x/1+x^2) Is the formula for Tan^-1(x) Diff. Dy/Dx= d(Tan^-1(x))/dx So .. 1/1+x^2 is the answer Hope it helps |
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