1.

-where 0 < x < 1 and 0<p<π/2,ir" Let y= sinThen d is equal to:dxdx

Answer»

For this you should know the formula of inverse trigonometric functions .

So sin^-1(2x/1+x^2)

Is the formula for Tan^-1(x)

Diff.

Dy/Dx= d(Tan^-1(x))/dx

So .. 1/1+x^2 is the answer

Hope it helps



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