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Which compound in each of the following pairs will react faster in SN2 reaction with–OH? Why?(i) CH3Br or CH3I(ii) (CH3)3CCl or CH3Cl |
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Answer» (i) CH3–I reacts faster than CH3–Br as iodine is a better leaving group because of its larger size. (ii) CH3–Cl (1° halide) reacts faster than (CH3)3CCl (3° halide) since in case tertiary butyl chloride three bulky methyl group hinder the approaching nucleophile. |
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