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Which of the following increasing order of oxidising power is correct for the following species? `VO_(2)^(+),MnO_(4)^(-),Cr_(2)O_(7)^(2-)`A. `VO_(2^(+)) lt Cr_(2)O_(7^(2))`B. `VO_(2^(+)) lt MnO_(4) lt Cr_(2)O_(7)^(2-)`C. `Cr_(2)O_(7^(2)) lt MnO_(4)`D. `Cr_(2)O_(7^(2-)) lt MnO_(4^(-)) lt VO_(2^(+))`. |
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Answer» Correct Answer - A This is attributed to the increasing stability of the lower species to which they are reduced. `MnO_(4)` is reduced to `Mn^(2+)` which has stable half filled valence shell electron configuration `[3d^(5)].Cr_(2)O_(7)^(2-)` is reduced to` Cr^(3+)` which has half filled `t_(2g)^(3)` energy level of 3d orbitals in octahedral crystal field spliting. `VO_(2^(+))` is reduced to `V^(3+)` which has electronic configuration `[Ar]^(18)3d^(2)4s^(0)` so the order of increasing stability of the reduced species is `Mn^(2+) gt Cr^(3+) gt V^(3+)` and, therefore, the increasing order of oxidising power is `VO_(2^(+)) lt Cr_(2)O_(7^(2-)) lt MnO_(4^(-))`. |
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