1.

Which of the following is not square planar ?

Answer»

`[PtCl_(4)]^(-2)`
`[Pt(CN)_(4)]^(-2)`
`[NiCl_(4)]^(-2)`
`[PdCl_(4)]^(-2)`

Solution :`[NiCl_(4)]^(-2)`has `sp^(3)` hybridised state due weak field nature of `Cl^(-)ion` but `Pt^(2+)andPd^(2+)(4^(TH)and5^(th)` trasition series) pairing of electron TAKES place irrespective of nature of ligand resulting in square planar complexes.]


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